C++ PROGRAMS (STAGE-II)



C++ PROGRAMS
 

//STAR PATTERN 1

#include<iostream.h>
#include<conio.h>
void main()
{
int count,i;
clrscr();
for(count=0;count<=10;count++)
{
for(i=0;i<=count;i++)
cout<<'*';
cout<<endl;
}
getch();
}
/* Output
*
**
***
****
*****
******
*******
********
*********
**********
***********
*/


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// STAR PATTERN 2

#include<iostream.h>
#include<conio.h>
void main()
{
int count,i;
clrscr();
for(count=10;count>=0;count--)
{
for(i=count;i>=0;i--)
cout<<'*';
cout<<endl;
}
getch();
}




/* OUTPUT
**********
*********
********
*******
******
*****
****
***
**
*
*/


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//ALPHABETS PATTERN 1

#include<iostream.h>
#include<conio.h>
void main()
{
clrscr ();
int count,i,n=26,k,j,m;
char ch;
for(i=1, m=65;i<=n;i++,m++)
{
for(k=1;k<=n-i;k++)
{
cout<<" ";
}
for(ch=65;ch<=m;ch++)
{
cout<<ch;
}
cout<<endl;
}
getch();
}


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// ALPHABETS PATTERN

#include<iostream.h>
#include<conio.h>
void main()
{
clrscr ();
int count,i,n=26,k,j,m;
char ch;
for(i=1, m=65;i<=n;i++,m++) // for line
{
for(k=1;k<=n-i;k++) // for white space
{
cout<<" ";
}
for(ch=65;ch<=m;ch++) // for elements in line
{
cout<<ch << " ";
}
cout<<endl;
}
getch();
}



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//COUNT POSITIVE AND NEGATIVE INPUTS IN TEN ENTRIES

#include<iostream.h>
#include<conio.h>
void main ()
{
int count=0, pcount=0, ncount=0, num;
clrscr ();
cout<<"\nENTER 10 NUMBER :\n";
for (count=0; count<10; count=count+1)
{
cin >> num;
if (num>0)
pcount=pcount+1;
else
ncount=ncount+1;
}
cout << "THE NUMBER OF POSITIVE INTEGERS : " << pcount << endl;
cout << "THE NUMBER OF NEGATIVE INTEGERS : " << ncount;
getch ();
}



/*OUTPUT
ENTER 10 NUMBER :
123
34
56
5
-54
-43
453
-45
-3
-89
THE NUMBER OF POSITIVE INTEGERS : 5
THE NUMBER OF NEGATIVE INTEGERS : 5
*/



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//TO DETERMINE A PERFECT NUMBER.

#include<iostream.h>
#include<conio.h>
void main ()
{
int num, fact, gfact, fsum=0;
clrscr ();
cout << "ENTER A NUMBER : ";
cin >> num;
gfact=(num/2)+1;
for (fact=1; fact<=gfact; fact=fact+1)
{
if (num%fact==0)
fsum+=fact;
}
if (fsum==num)
cout << "\nIT IS A PERFECT NUMBER. " << endl;
else
cout << "\nIT IS NOT A PERFECT NUMBER. " << endl;
getch ();
}



/*OUTPUT
ENTER A NUMBER : 6
IT IS A PERFECT NUMBER.
ENTER A NUMBER : 25
IT IS NOT A PERFECT NUMBER.
*/


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// TO DETERMINE A PRIME NUMBER.

#include<iostream.h>
#include<conio.h>
void main ()
{
long num, fact; int count;
clrscr ();
cout << "ENTER A NUMBER : ";
cin >> num;
for ( fact=1, count=0; fact<=num/2; fact=fact+1)
{
if (num%fact==0)
count=count+1;
}
if (count==1)
cout << "\nYES! ITS IS A PRIME NUMBER." << endl;
else
cout << "\nNO! IT IS NOT A PRIME NUMBER." << endl;
getch ();
}



/*OUTPUT
ENTER A NUMBER : 3
YES! ITS IS A PRIME NUMBER.
ENTER A NUMBER : 23
YES! ITS IS A PRIME NUMBER.
ENTER A NUMBER : 9
NO! IT IS NOT A PRIME NUMBER.
*/



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// PRINT THE MULTIPLES OF A NUMBER USING A DO-WHILE LOOP;

#include<iostream.h>
#include<conio.h>
void main()
{
int num, multi=0;
clrscr();
cout<<"\nPLEASE ENTER THE NUMBER : ";
cin>>num;
cout<<"\nTHE MULTIPLES OF " <<num <<" are : " <<endl << endl;
do
{
multi++;
cout <<num << " X " << multi << " = " << num*multi << endl;
} while(multi<10);
getch();
}



/* Output
a)
PLEASE ENTER THE NUMBER : 63
THE MULTIPLES OF 63 are :
63 X 1 = 63
63 X 2 = 126
63 X 3 = 189
63 X 4 = 252
63 X 5 = 315
63 X 6 = 378
63 X 7 = 441
63 X 8 = 504
63 X 9 = 567
63 X 10 = 630
b)
PLEASE ENTER THE NUMBER : 1539
THE MULTIPLES OF 1539 are :
1539 X 1 = 1539
1539 X 2 = 3078
1539 X 3 = 4617
1539 X 4 = 6156
1539 X 5 = 7695
1539 X 6 = 9234
1539 X 7 = 10773
1539 X 8 = 12312
1539 X 9 = 13851
1539 X 10 = 15390
*/



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// PRINT THE MULTIPLICATION TABLE OF A NUMBER USING A FOR LOOP;

#include<iostream.h>
#include<conio.h>
void main()
{
int num, multi;
clrscr();
cout<<"\nPLEASE ENTER THE NUMBER : ";
cin>>num;
cout<<"\nTHE MULTIPLES OF " <<num <<" are : " <<endl << endl;
for(multi=1; multi<=10; multi++)
{
cout<< num<<" X " <<multi << " = " << num*multi <<endl;
}
getch();
}



/* Output
a)
PLEASE ENTER THE NUMBER : 81
THE MULTIPLES OF 81 are :
81 X 1 = 81
81 X 2 = 162
81 X 3 = 243
81 X 4 = 324
81 X 5 = 405
81 X 6 = 486
81 X 7 = 567
81 X 8 = 648
81 X 9 = 729
81 X 10 = 810
b)
PLEASE ENTER THE NUMBER : 2745
THE MULTIPLES OF 2745 are :
2745 X 1 = 2745
2745 X 2 = 5490
2745 X 3 = 8235
2745 X 4 = 10980
2745 X 5 = 13725
2745 X 6 = 16470
2745 X 7 = 19215
2745 X 8 = 21960
2745 X 9 = 24705
2745 X 10 = 27450
*/



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// REVERSE OF A NUMBER INPUT THE USER

#include<iostream.h>
#include<conio.h>
void main()
{
char choice;
do
{
long num,reverse=0, count, t1;
clrscr();
cout<<"\nENTER A NUMBER : ";
cin>>num;
while (num != 0)
{
t1=num%10;
reverse=(reverse*10)+t1;
num=num/10;
}
cout<<"\nTHE REVERSE NUMBER IS : "<<reverse<<endl;
cout<<"\nREPEAT THE PROGRAM? (y/n) : ";
cin>>choice;
}while(choice=='y'||choice=='Y');
}


/* OUTPUT
a)
ENTER A NUMBER : 63
THE REVERSE NUMBER IS : 36
REPEAT THE PROGRAM? (y/n) : y
b)
ENTER A NUMBER : 854556
THE REVERSE NUMBER IS : 655458
REPEAT THE PROGRAM? (y/n) : y
c)
ENTER A NUMBER : 38978231
THE REVERSE NUMBER IS : 13287983
REPEAT THE PROGRAM? (y/n) : y
d)
ENTER A NUMBER : 4352496
THE REVERSE NUMBER IS : 6942534
REPEAT THE PROGRAM? (y/n) : n
*/



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//A PROGRAM TO DISPLAY AN ARITHMETIC PROGRESSION : 1 , 2 , 3 , 4 , 5 ,.....N

#include<iostream.h>
#include<conio.h>
void main()
{
long double i, n;
clrscr();
cout<<"\nEnter the number of elements for the series : ";
cin>>n;
gotoxy(1,4);
for(i=1; i<=n; i++)
cout<<i<<"\t";
getch();
}




/* Output
a)
Enter the number of elements for the series : 15
1 2 3 4 5 6 7 8 9 10
11 12 13 14 15
b)
Enter the number of elements for the series : 30
1 2 3 4 5 6 7 8 9 10
11 12 13 14 15 16 17 18 19 20
21 22 23 24 25 26 27 28 29 30
c)
Enter the number of elements for the series : 81
1 2 3 4 5 6 7 8 9 10
11 12 13 14 15 16 17 18 19 20
21 22 23 24 25 26 27 28 29 30
31 32 33 34 35 36 37 38 39 40
41 42 43 44 45 46 47 48 49 50
51 52 53 54 55 56 57 58 59 60
61 62 63 64 65 66 67 68 69 70
71 72 73 74 75 76 77 78 79 80
81



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// PRINT THE SERIES : -1, +4, -9, +16....N

#include<iostream.h>
#include<conio.h>
void main()
{
clrscr();
int num, even, odd, sum, count1, count2, temp1=1, temp2;
cout<<"Enter the number of elements : ";
cin>>num;
cout<<"\n";
for(count1=1,count2=2;temp1<=num/2;count1+=2,count2+=2,temp1++)
{
even=count2*count2;
odd=count1*count1;
temp2=odd-(2*odd);
cout<<temp2<<"\t";
cout<<even<<"\t";
}
if(num%2!=0)
{
odd=count1*count1;
temp2=odd-(2*odd);
cout<<temp2;
}
getch();
}




/* Output
a)
Enter the number of elements : 10
-1 4 -9 16 -25 36 -49 64 -81 100
b)
Enter the number of elements : 34
-1 4 -9 16 -25 36 -49 64 -81 100
-121 144 -169 196 -225 256 -289 324 -361 400
-441 484 -529 576 -625 676 -729 784 -841 900
-961 1024 -1089 1156
c)
Enter the number of elements : 63
-1 4 -9 16 -25 36 -49 64 -81 100
-121 144 -169 196 -225 256 -289 324 -361 400
-441 484 -529 576 -625 676 -729 784 -841 900
-961 1024 -1089 1156 -1225 1296 -1369 1444 -1521 1600
-1681 1764 -1849 1936 -2025 2116 -2209 2304 -2401 2500
-2601 2704 -2809 2916 -3025 3136 -3249 3364 -3481 3600
-3721 3844 -3969
*/



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// A SERIES WITH 2 APS : 0,2,5,9,14,20,27,35....N

#include<iostream.h>
#include<conio.h>
void main()
{
clrscr();
int n,i,sum;
cout<<"Enter the nth term : ";
cin>>n;
cout<<"\n";
for(i=2, sum=0; i<=n;i++)
{
cout<<sum << "\t" ;
sum+=i;
}
cout<<sum;
getch();
}



/* Output
a)
Enter the nth term : 7
0 2 5 9 14 20 27
b)
Enter the nth term : 18
0 2 5 9 14 20 27 35 44 54
65 77 90 104 119 135 152 170
c)
Enter the nth term : 25
0 2 5 9 14 20 27 35 44 54
65 77 90 104 119 135 152 170 189 209
230 252 275 299 324
d)
Enter the nth term : 36
0 2 5 9 14 20 27 35 44 54
65 77 90 104 119 135 152 170 189 209
230 252 275 299 324 350 377 405 434 464
495 527 560 594 629 665
e)
Enter the nth term : 45
0 2 5 9 14 20 27 35 44 54
65 77 90 104 119 135 152 170 189 209
230 252 275 299 324 350 377 405 434 464
495 527 560 594 629 665 702 740 779 819
860 902 945 989 1034
*/



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// TO DISPLAY SERIES : 2,6,12,20,30,42,56.......N

#include<iostream.h>
#include<conio.h>
void main()
{
int sum=0, i,n, t;
clrscr();
cout<<"Enter the number of terms : ";
cin>>n;
cout<<"\n";
for(i=2, t=1; t<=n; t++,i=i+2)
{
cout<<sum<<"\t";
sum+=i;
}
getch();
}



/* Output
a)
Enter the number of terms : 9
0 2 6 12 20 30 42 56 72
b)
Enter the number of terms : 15
0 2 6 12 20 30 42 56 72 90
110 132 156 182 210
c)
Enter the number of terms : 24
0 2 6 12 20 30 42 56 72 90
110 132 156 182 210 240 272 306 342 380
420 462 506 552
d)
Enter the number of terms : 43
0 2 6 12 20 30 42 56 72 90
110 132 156 182 210 240 272 306 342 380
420 462 506 552 600 650 702 756 812 870
930 992 1056 1122 1190 1260 1332 1406 1482 1560
1640 1722 1806
e)
Enter the number of terms : 63
0 2 6 12 20 30 42 56 72 90
110 132 156 182 210 240 272 306 342 380
420 462 506 552 600 650 702 756 812 870
930 992 1056 1122 1190 1260 1332 1406 1482 1560
1640 1722 1806 1892 1980 2070 2162 2256 2352 2450
2550 2652 2756 2862 2970 3080 3192 3306 3422 3540
3660 3782 3906
*/



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// PRINT THE FIBONACCI SERIES

#include<iostream.h>
#include<conio.h>
void main()
{
/* FIBONACCI SERIES */
char choice;
do
{
clrscr();
long double num, a=1, b=0, count;
cout<<"ENTER THE NUMBER OF ELEMENTS REQUIRED : ";
cin>>num;
cout<<"\n\n";
for(count=1; count<=num/2;count++)
{
a+=b;
cout<<b << "\t";
b+=a;
cout<<a << "\t";
}
cout<<"\n\nREPEAT THE SAME PROGRAM? (Y/N) : ";
cin>>choice;
}while(choice=='y'||choice=='Y');
}



/* Output
a)
ENTER THE NUMBER OF ELEMENTS REQUIRED : 8
0 1 1 2 3 5 8 13
REPEAT THE SAME PROGRAM? (Y/N) : y
b)
ENTER THE NUMBER OF ELEMENTS REQUIRED : 36
0 1 1 2 3 5 8 13 21 34
55 89 144 233 377 610 987 1597 2584 4181
6765 10946 17711 28657 46368 75025 121393 196418 317811 514229
832040 1346269 2178309 3524578 5702887 9227465
REPEAT THE SAME PROGRAM? (Y/N) : y
c)
ENTER THE NUMBER OF ELEMENTS REQUIRED : 28
0 1 1 2 3 5 8 13 21 34
55 89 144 233 377 610 987 1597 2584 4181
6765 10946 17711 28657 46368 75025 121393 196418
REPEAT THE SAME PROGRAM? (Y/N) : N



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// AVERAGE OF N NUMBERS

#include<iostream.h>
#include<conio.h>
void main()
{
long float result ;
long num,n, sum=0, count=0;
clrscr();
cout << "\nENTER THE NUMBER OF TERMS : ";
cin >> n;
for(count=0;count<n;sum+=num,count++)
{
cout<<"\nENTER A TERM : ";
cin>>num;
}
result=sum/n;
cout<<"\nTHE AVERAGE OF NUMBERS IS " << result;
getch();
}



/*OUTPUT
ENTER THE NUMBER OF TERMS : 15
ENTER A TERM : 231
ENTER A TERM : 324
ENTER A TERM : 456
ENTER A TERM : 675
ENTER A TERM : 768
ENTER A TERM : 6
ENTER A TERM : 4566
ENTER A TERM : 87876
ENTER A TERM : 546
ENTER A TERM : 7457
ENTER A TERM : 5646
ENTER A TERM : 675
ENTER A TERM : 4356
ENTER A TERM : 6758
ENTER A TERM : 54678
THE AVERAGE OF NUMBERS IS 11667
*/



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// SUM OF FRACTIONS FROM 1 ... 1/N

#include<iostream.h>
#include<conio.h>
void main()
{
char des;
clrscr();
do
{
long float num,temp, sum=0;
clrscr();
cout<<"ENTER THE VALUE FOR nth DENOMINATOR : " ;
cin>>num;
cout<<"\n";
for(temp=1;temp<=num;temp++)
{
sum=sum+(1/temp);
cout<<sum << " + ";
}
cout<<"\n\nTHE SUM IS : "<<sum;
cout<<"\n\nREPEAT? (y/n) : ";
cin>>des;
} while(des=='y'||des=='Y');
}



/*Output
a)
ENTER THE VALUE FOR nth DENOMINATOR : 7
1 + 1.5 + 1.833333 + 2.083333 + 2.283333 + 2.45 + 2.592857 +
THE SUM IS : 2.592857
REPEAT? (y/n) : y
b)
ENTER THE VALUE FOR nth DENOMINATOR : 18
1 + 1.5 + 1.833333 + 2.083333 + 2.283333 + 2.45 + 2.592857 + 2.717857 + 2.828968
+ 2.928968 + 3.019877 + 3.103211 + 3.180134 + 3.251562 + 3.318229 + 3.380729 +
3.439553 + 3.495108 +
THE SUM IS : 3.495108
REPEAT? (y/n) : n



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//CALCULATE THE FACTORS OF A GIVEN NUMBER

#include<iostream.h>
#include<conio.h>
void main ()
{
int num, fact, gfact;
clrscr ();
cout<<"ENTER A NUMBER : ";
cin >> num;
gfact=num/2;
cout<<"THE FACTORS OF " << num << " ARE : " << endl;
for ( fact=1; fact<=gfact; fact=fact+1)
{
if (num%fact==0)
cout << fact << endl;
}
getch ();
}


/*OUTPUT
ENTER A NUMBER : 90
THE FACTORS OF 90 ARE :
1
2
3
5
6
9
10
15
18
30
45
*/



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// FACTORIAL OF A NUMBER

#include<iostream.h>
#include<conio.h>
void main()
{
char choice;
do
{
clrscr();
long double num, i, fact=1;
cout<<"\nENTER THE NUMBER : ";
cin>>num;
for(i=num;i>=1;i--)
fact=fact*i;
cout<<"\nTHE FACTORIAL OF " << num <<" IS " << fact;
cout<<"\n\nREPEAT THE PROGRAM (y/n) : ";
cin>>choice;
}while(choice=='y'||choice=='Y');
}



/*Output
a)
ENTER THE NUMBER : 63
THE FACTORIAL OF 63 IS 1.982608e+87
REPEAT THE PROGRAM (y/n) : y
b)
ENTER THE NUMBER : 81
THE FACTORIAL OF 81 IS 5.797126e+120
REPEAT THE PROGRAM (y/n) : y
c)
ENTER THE NUMBER : 7
THE FACTORIAL OF 7 IS 5040
REPEAT THE PROGRAM (y/n) : y
d)
ENTER THE NUMBER : 9
THE FACTORIAL OF 9 IS 362880
REPEAT THE PROGRAM (y/n) : y
e)
ENTER THE NUMBER : 18
THE FACTORIAL OF 18 IS 6.402374e+15
REPEAT THE PROGRAM (y/n) : n
*/



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// TO CALCULATE THE SUM OF DIGITS IN A NUMBER

#include<iostream.h>
#include<conio.h>
void main ()
{
long num, digit, sum;
clrscr();
cout << " ENTER A NUMBER : ";
cin >> num;
for (sum=0; num!=0; num=num/10)
{
digit=num%10;
sum=sum+digit;
}
cout << "\nTHE SUM OF THE DIGITS : "<<sum;
getch();
}



/*OUTPUT
ENTER A NUMBER : 98250237
THE SUM OF THE DIGITS : 36
*/



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// COMPOUND INTEREST BY SIMPLE INTEREST

#include<iostream.h>
#include<conio.h>
void main()
{
long float interest, prince, rate, amt;
int time, temp, r;
char choice;
do
{
clrscr ();
cout<<"PLEASE ENTER THE PRINCIPAL AMOUNT : ";
cin>>prince;
cout<<"\nENTER THE RATE OF INTEREST : ";
cin>>rate;
cout<<"\nENTER THE TIME : ";
cin>>time;
amt=prince;
cout<<"\n\tTIME\tSIMPLE INTEREST\tAMOUNT";
for(r=8, temp=0,interest=0;temp<=time;temp++, r++)
{
cout<<"\n\t"<<temp<<"\t"<<interest;
gotoxy(33,r);
cout<<amt;
interest=(amt*rate)/100;
amt=amt+interest;
}
cout<<"\n\tClosing"<<"\t"<<interest;
cout<<amt;
cout<<"\n\nTHUS, THE FINAL AMOUNT IS : "<<amt;
cout<<"\n\nREPEAT? (y/n) : ";
cin>>choice;
if(choice=='n'||choice=='N')
cout<<"\nTHANK YOU";
getch();
}while(choice=='y'||choice=='Y');
}




/* OUTPUT
a)
PLEASE ENTER THE PRINCIPAL AMOUNT : 30000
ENTER THE RATE OF INTEREST : 10
ENTER THE TIME : 5
TIME SIMPLE INTEREST AMOUNT
0 0 30000
1 3000 33000
2 3300 36300
3 3630 39930
4 3993 43923
5 4392.3 48315.3
Closing 4831.53 53146.83
THUS, THE FINAL AMOUNT IS : 53146.83
REPEAT? (y/n) : n



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// SIMPLE CALCULATOR FOR 2 FRACTIONS

#include<iostream.h>
#include<conio.h>
#include<process.h>
void main()
{
float num1,num2,den1,den2,result;
char sign, choice;
do
{
clrscr();
cout<<"FRACTION 1 : "<<endl;
cout<<"\nENTER THE NUMERATOR : ";
cin>>num1;
cout<<"\nENTER THE DENOMINATOR : ";
cin>>den1;
cout<<"\nENTER THE CALCULATION OPERATOR (+, -, *, /) : ";
cin>>sign;
cout<<"\nFRACTION 2 : "<<endl;
cout<<"\nENTER THE NUMERATOR : ";
cin>>num2;
cout<<"\nENTER THE DENOMINATOR : ";
cin>>den2;
if(num1==0 || num2==0 || den1==0 || den2==0)
{
cout<<"\nOOPS!!! INVALID ENTRY. BYE! ";
exit(0);
}
switch(sign)
{
case '+': result=((num1/den1)+(num2/den2)); break;
case '-': result=((num1/den1)-(num2/den2)); break;
case '*': result=((num1/den1)*(num2/den2)); break;
case '/': result=((num1/den1)/(num2/den2)); break;
default :
cout<<"\nOOPS!!!INVALID CALCULATION OPERATOR. BYE!!";
exit(0);
}
cout<<"\nRESULT IS : "<<result;
cout<<"\n\nDO YOU WISH TO RE-EXECUTE THE PROGRAM? (Y/N) : ";
cin>>choice;
}while(choice=='y'||choice=='Y');
}


/*OUTPUT
FRACTION 1 :
ENTER THE NUMERATOR : 12
ENTER THE DENOMINATOR : 23
ENTER THE CALCULATION OPERATOR (+, -, *, /) : *
FRACTION 2 :
ENTER THE NUMERATOR : 12
ENTER THE DENOMINATOR : 23
RESULT IS : 0.272212
DO YOU WISH TO RE-EXECUTE THE PROGRAM? (Y/N) : n */




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// SUM OF ALL TERMS OF AN ARRAY INPUT BY THE USER

#include<iostream.h>
#include<conio.h>
void main()
{
clrscr(); long float num[10], sum=0, y=1;
cout<<"\nEnter 10 elements for the array : "<<endl<<endl;
for(;y<=10;y++)
{
cout<<"\nEntry : "<<y<<endl<<endl; cout<<"Enter : ";
cin>>num[y]; sum+=num[y];
}
cout<<"\n\nThe sum all the elements entered for the array is : " << sum;
getch();
}



/* Output
Enter 10 elements for the array :
Entry : 1
Enter : 1
Entry : 2
Enter : 22
Entry : 3
Enter : 345
Entry : 4
Enter : 454
Entry : 5
Enter : 67
Entry : 6
Enter : 234
Entry : 7
Enter : 564
Entry : 8
Enter : 234
Entry : 9
Enter : 563
Entry : 10
Enter : 673
The sum all the elements entered for the array is : 3157
*/



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/* TO ACCEPT 10 NUMBERS IN AN ARRAY AND PRINT THE SUM OF:
ALL ODD ELEMENTS IN THE ARRAY
ALL EVEN ELEMENTS IN THE ARRAY
EVERY 3RD ELEMENT IN THE ARRAY */

#include<iostream.h>
#include<conio.h>
void main()
{
int array[10], count=0, sum1=0, sum2=0, sum3=0;
clrscr();
//*********input**************
cout<<"\nENTER 10 NUMBERS FOR THE ARRAY : " <<endl<<endl;
for(count=0;count<10;count++)
{
cin >> array[count];
}
//************process***********
for(count=0 ; count<10 ; count++)
{
if(count%2!=0)
sum1=sum1+array[count];
else
sum2=sum2+array[count];
}
for(count=2 ; count<10 ; count=count+3)
{
sum3=sum3+array[count];
}
//**************output***********
cout<<"\nTHE RESULTS ARE : " << endl;
cout<<"\n1: "<<"SUM OF ALL ODD ELEMENTS : "<<sum1<<endl;
cout<<"\n2: "<<"SUM OF ALL EVEN ELEMENTS : "<<sum2<<endl;
cout<<"\n3: "<<"SUM OF EVERY 3rd ELEMENT IN THE ARRAY : "<< sum3 <<endl;
getch();
}



/*OUTPUT
ENTER 10 NUMBERS FOR THE ARRAY :
12
23
34
45
56
67
78
89
90
99
THE RESULTS ARE :
1: SUM OF ALL ODD ELEMENTS : 323
2: SUM OF ALL EVEN ELEMENTS : 270
3: SUM OF EVERY 3rd ELEMENT IN THE ARRAY : 191
*/

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// INPUT 3 DIGITS AND FORM A NEW NUMBER

#include<iostream.h>
#include<conio.h>
void main()
{
char choice, ch1,ch2, ch3, ch4, s[4];
int dig1, dig2, dig3, num2, num3, num4, num5, num6;
do
{
clrscr();
cout<<"\nENTER THREE DIGIT CHARACTER : \n";
cin>>s;
ch1=s[0];
ch2=s[1];
ch3=s[2];
dig1=(ch1-'0');
dig2=(ch2-'0');
dig3=(ch3-'0');
num2=dig1*100 + dig3*10 + dig2;
num3=dig2*100 + dig3*10 + dig1;
num4=dig2*100 + dig1*10 + dig3;
num5=dig3*100 + dig2*10 + dig1;
num6=dig3*100 + dig1*10 + dig2;
cout<<"\nTHE NUMBERS FORMED ARE : \n"<< num2;
cout<<"\n" <<num3<<"\n"<<num4<<"\n"<<num5<<"\n"<<num6;
cout<<"\n\nDO YOU WISH TO REPEAT THE PROGRAM? (Y/N) : ";
cin>>choice;
}while(choice=='y'||choice=='Y');
}
/*OUTPUT
ENTER THREE DIGIT CHARACTER :
345
THE NUMBERS FORMED ARE :
354
453
435
543
534
DO YOU WISH TO REPEAT THE PROGRAM? (Y/N) : n
*/




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/* PRINT THE BILL INDEX OF ALL USERS ALONG WITH THEIR ELECTRICITY CONSUMPTION UNITS AND THE BILL TO BE PAYED.*/

#include<iostream.h>
#include<conio.h>
void main()
{
long consumption[25], charges[25];
int count, y;
char name[5][25];
clrscr();
for(count=0; count<5; count++)
{
cout<<"ENTER THE NAME : ";
cin>>name[count];
cout<<"ENTER THE ELECTRICITY CONSUMPTION : ";
cin >> consumption[count];
if(consumption[count]<=400)
charges[count]=consumption[count]*60;
else if (consumption[count]>400 && consumption[count]<=900)
charges[count]=((consumption[count]-100)*80) + 6000;
else if(consumption[count]>900)
charges[count]=((consumption[count]-300)*90) + 22000;
}
clrscr();
gotoxy(1,1);
cout << "NAME";
gotoxy(7,1);
cout << "CONSUMPTION";
gotoxy(20,1);
cout << "CHARGES" <<endl;
for(count=0, y=3; count<5; count++, y++)
{
gotoxy(1,y);
cout<<name[count];
gotoxy(12,y);
cout<<consumption[count];
gotoxy(20,y);
cout<<charges[count];
}
getch();
}



/*OUTPUT
ENTER THE NAME : VISHAL
ENTER THE ELECTRICITY CONSUMPTION : 950
ENTER THE NAME : RAVI
ENTER THE ELECTRICITY CONSUMPTION : 750
ENTER THE NAME : RAM
ENTER THE ELECTRICITY CONSUMPTION : 375
ENTER THE NAME : MOHAN
ENTER THE ELECTRICITY CONSUMPTION : 625
ENTER THE NAME : HARSH
ENTER THE ELECTRICITY CONSUMPTION : 1200
NAME CONSUMPTION CHARGES
VISHAL 950 80500
RAVI 750 58000
RAM 375 22500
MOHAN 625 48000
HARSH 1200 103000 */




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// EMPLOYEE PAY-SLIP

#include<iostream.h>
#include<conio.h>
void main()
{
char choice;
do
{
char name[5][15];
long int count, eno[5], basic[5], hra[5], da[5], pf[5], it[5],
gross_sal[5], gross_ded[5], net[5];
clrscr();
for(count=0;count<5;count++)
{
cout<<"\nEnter name : ";
cin>>name[count];
cout<<"Enter employee number : ";
cin>>eno[count];
cout<<"Enter Basic Salary : ";
cin>>basic[count];
hra[count]=0.55*basic[count];
da[count]=0.20*basic[count];
it[count]=0.30*basic[count];
pf[count]=0.10*basic[count];
gross_sal[count]=basic[count]+hra[count]+da[count];
gross_ded[count]=it[count]+pf[count];
net[count]=gross_sal[count]-gross_ded[count];
}
clrscr();
cout<<"Employee Payslip\n\n";
cout<<"Number\t" <<"Name\t" << "Basic\t" << "Gr.Sal\t" << "Gr.Ded\t";
cout<<"Net Salary\n\n";
for(count=0;count<5;count++)
{
cout<<eno[count]<<"\t"<<name[count]<<"\t"<<basic[count]
<<"\t"<<gross_sal[count] <<"\t"<< gross_ded[count]<<"\t"
<<net[count]<<"\n\n";
}
cout<<"\n\nRepeat ?(y/n) : ";
cin>>choice;
}while(choice=='y'||choice=='Y');
}




/* Output
Enter name : Vipul
Enter employee number : 1
Enter Basic Salary : 76937
Enter name : Rachit
Enter employee number : 2
Enter Basic Salary : 63636
Enter name : Kunchit
Enter employee number : 3
Enter Basic Salary : 89376
Enter name : Ganesh
Enter employee number : 4
Enter Basic Salary : 74893
Enter name : Kunj
Enter employee number : 5
Enter Basic Salary : 92834
Employee Payslip
Number Name Basic Gr.Sal Gr.Ded Net Salary
1 Vipul 76937 134639 30774 103865
2 Rachit 63636 111362 25453 85909
3 Kunchit 89376 156407 35749 120658
4 Ganesh 74893 131062 29956 101106
5 Kunj 92834 162458 37133 125325
Repeat ?(y/n) :n
*/


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